Intel® Integrated Performance Primitives (Intel® IPP) Developer Guide and Reference
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Min
Computes the minimum of image pixel values.
Syntax
Case 1: Operation on one-channel data
IppStatus ippiMin_<mod>(const Ipp<datatype>* pSrc, int srcStep, IppiSize roiSize, Ipp<datatype>* pMin);
Supported values for mod:
| 8u_C1R | 16u_C1R | 16s_C1R | 32f_C1R | 
Case 2: Operation on multi-channel data
IppStatus ippiMin_<mod>(const Ipp<datatype>* pSrc, int srcStep, IppiSize roiSize, Ipp<datatype> min[3]);
Supported values for mod:
| 8u_C3R | 16u_C3R | 16s_C3R | 32f_C3R | 
| 8u_AC4R | 16u_AC4R | 16s_AC4R | 32f_AC4R | 
IppStatus ippiMin_<mod>(const Ipp<datatype>* pSrc, int srcStep, IppiSize roiSize, Ipp<datatype> min[4]);
Supported values for mod:
| 8u_C4R | 16u_C4R | 16s_C4R | 32f_C4R | 
Include Files
ippi.h
Domain Dependencies
Headers: ippcore.h, ippvm.h, ipps.h
Libraries: ippcore.lib, ippvm.lib, ipps.lib
Parameters
| pSrc | Pointer to the source image ROI. | 
| srcStep | Distance in bytes between starts of consecutive lines in the source image. | 
| roiSize | Size of the source ROI in pixels. | 
| pMin | Pointer to the minimum pixel value (for one-channel data). | 
| min | Array containing minimum channel values of pixels in the source buffer (for multi-channel data). | 
Description
This function operates with ROI (see Regions of Interest in Intel IPP). This function computes the minimum pixel value pMin for the source image pSrc. In case of a multi-channel image, the minimum is computed over each channel and stored in the array min.
Return Values
| ippStsNoErr | Indicates no error. Any other value indicates an error or a warning. | 
| ippStsNullPtrErr | Indicates an error condition if pSrc or pMin pointer is NULL. | 
| ippStsSizeErr | Indicates an error condition if roiSize has a field with zero or negative value. | 
Example
The code example below demonstrates how to use the function ippiMin.
Ipp8u src[4*1] = { 40, 20, 60, 80 };
IppiSize roiSize = { 4, 1 };
Ipp8u min;
ippiMin_8u_C1R ( src, 4, roiSize, &min ); 
    
   Result:
min = 20