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Intel® oneAPI Math Kernel Library LAPACK Examples

ID 766877
Date 3/31/2023
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ZGELS Example Program in C

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/*
   ZGELS Example.
   ==============

   Program computes the minimum norm solution to the underdetermined linear
   system A*X = B with full rank matrix A using LQ factorization,
   where A is the coefficient matrix:

   ( -4.20, -3.44) ( -3.35,  1.52) (  1.73,  8.85) (  2.35,  0.34)
   ( -5.43, -8.81) ( -4.53, -8.47) (  5.93,  3.75) ( -3.75, -5.66)
   ( -5.56,  3.39) (  2.90, -9.22) (  8.03,  9.37) (  5.69, -0.47)

   and B is the right-hand side matrix:

   ( -7.02,  4.80) (  3.88, -2.59)
   (  0.62, -2.40) (  1.57,  3.24)
   (  3.10, -2.19) ( -6.93, -5.99)

   Description.
   ============

   The routine solves overdetermined or underdetermined complex linear systems
   involving an m-by-n matrix A, or its transpose, using a QR or LQ
   factorization of A. It is assumed that A has full rank.

   Several right hand side vectors b and solution vectors x can be handled
   in a single call; they are stored as the columns of the m-by-nrhs right
   hand side matrix B and the n-by-nrhs solution matrix X.

   Example Program Results.
   ========================

 ZGELS Example Program Results

 Minimum norm solution
 ( -0.25, -0.04) ( -0.21,  0.42)
 (  0.99,  0.27) ( -0.21, -0.43)
 (  0.25,  0.43) ( -0.24, -0.13)
 ( -0.32,  0.14) ( -0.23, -0.09)

 Details of LQ factorization
 ( 11.40,  0.00) (  0.18, -0.14) ( -0.23, -0.52) ( -0.15,  0.01)
 (  7.73, -0.39) ( 15.32,  0.00) ( -0.22,  0.42) (  0.45,  0.17)
 (  8.60, -5.68) (  3.96,  6.46) ( 12.54,  0.00) ( -0.02, -0.47)
*/
#include <stdlib.h>
#include <stdio.h>

/* Complex datatype */
struct _dcomplex { double re, im; };
typedef struct _dcomplex dcomplex;

/* ZGELS prototype */
extern void zgels( char* trans, int* m, int* n, int* nrhs, dcomplex* a,
                int* lda, dcomplex* b, int* ldb, dcomplex* work, int* lwork, int* info );
/* Auxiliary routines prototypes */
extern void print_matrix( char* desc, int m, int n, dcomplex* a, int lda );

/* Parameters */
#define M 3
#define N 4
#define NRHS 2
#define LDA M
#define LDB N

/* Main program */
int main() {
        /* Locals */
        int m = M, n = N, nrhs = NRHS, lda = LDA, ldb = LDB, info, lwork;
        dcomplex wkopt;
        dcomplex* work;
        /* Local arrays */
        dcomplex a[LDA*N] = {
           {-4.20, -3.44}, {-5.43, -8.81}, {-5.56,  3.39},
           {-3.35,  1.52}, {-4.53, -8.47}, { 2.90, -9.22},
           { 1.73,  8.85}, { 5.93,  3.75}, { 8.03,  9.37},
           { 2.35,  0.34}, {-3.75, -5.66}, { 5.69, -0.47}
        };
        dcomplex b[LDB*NRHS] = {
           {-7.02,  4.80}, { 0.62, -2.40}, { 3.10, -2.19}, { 0.00,  0.00},
           { 3.88, -2.59}, { 1.57,  3.24}, {-6.93, -5.99}, { 0.00,  0.00}
        };
        /* Executable statements */
        printf( " ZGELS Example Program Results\n" );
        /* Query and allocate the optimal workspace */
        lwork = -1;
        zgels( "No transpose", &m, &n, &nrhs, a, &lda, b, &ldb, &wkopt, &lwork,
                        &info );
        lwork = (int)wkopt.re;
        work = (dcomplex*)malloc( lwork*sizeof(dcomplex) );
        /* Solve the equations A*X = B */
        zgels( "No transpose", &m, &n, &nrhs, a, &lda, b, &ldb, work, &lwork,
                        &info );
        /* Check for the full rank */
        if( info > 0 ) {
                printf( "The diagonal element %i of the triangular factor ", info );
                printf( "of A is zero, so that A does not have full rank;\n" );
                printf( "the minimum norm solution could not be computed.\n" );
                exit( 1 );
        }
        /* Print minimum norm solution */
        print_matrix( "Minimum norm solution", n, nrhs, b, ldb );
        /* Print details of LQ factorization */
        print_matrix( "Details of LQ factorization", m, n, a, lda );
        /* Free workspace */
        free( (void*)work );
        exit( 0 );
} /* End of ZGELS Example */

/* Auxiliary routine: printing a matrix */
void print_matrix( char* desc, int m, int n, dcomplex* a, int lda ) {
        int i, j;
        printf( "\n %s\n", desc );
        for( i = 0; i < m; i++ ) {
                for( j = 0; j < n; j++ )
                        printf( " (%6.2f,%6.2f)", a[i+j*lda].re, a[i+j*lda].im );
                printf( "\n" );
        }
}