Visible to Intel only — GUID: GUID-B38EB11C-0468-4499-B5A6-2CC4928574B5
Visible to Intel only — GUID: GUID-B38EB11C-0468-4499-B5A6-2CC4928574B5
GetOctString_BN
Converts a positive Big Number into octet String.
Syntax
IppStatus ippsGetOctString_BN(Ipp8u* pStr, int strLen, const IppsBigNumState* pBN);
Include Files
ippcp.h
Parameters
pStr |
Pointer to the input octet string. |
strLen |
Octet string length in bytes. |
pBN |
Pointer to the context of the input Big Number. |
Description
This function converts a positive Big Number into the octet string.
Return Values
ippStsNoErr |
Indicates no error. Any other value indicates an error or warning. |
ippStsNullPtrErr |
Indicates an error condition if any of the specified pointers is NULL. |
ippStsContextMatchErr |
Indicates an error condition if the context parameter does not match the operation. |
ippStsLengthErr |
Indicates an error condition if specified pStr is insufficient in length. |
ippStsRangeErr |
Indicates an error condition if Big Number is negative. |
Example
The code example below types a big number.
void Type_BN(const char* pMsg, const IppsBigNumState* pBN){ // size of Big Number int size; ippsGetSize_BN(pBN, &size); // extract Big Number value and convert it to the string presentation Ipp8u* bnValue = new Ipp8u [size*4]; ippsGetOctString_BN(bnValue, size*4, pBN); // type header if(pMsg) cout<<pMsg; // type value for(int n=0; n<size*4; n++) cout<<hex<<setfill('0')<<setw(2)<<(int)bnValue[n]; cout<<endl; delete [] bnValue; }